Question

X^2 = x+12 por favor me ajudem

Answer 1

$x+12-x^2 = 0 \\ b^2 - 4.a.c \\ 1^2 - 4.(-1).12 \\ 1+48 \\ 49 \\ -1+/- \sqrt{49}/2.(-1) \\ -1+/-7/-2 \\ x' = 4 \\ x'' = -3$