Question

- x ^ 2 + x + 12 = 0

Answer 1

Resposta:

x' = 4

x'' = - 3

Explicação passo a passo:

$-x^{2} + x + 12 = 0\\x^{2} - x - 12 = 0\\\\a = 1\\b - 1\\c = -12\\\\x = \frac{-(b) +- \sqrt{b^{2} - 4 .a.c} }{2a} \\x = \frac{-(-1) +- \sqrt{(-1^{2}) - 4 .1.(-12)} }{2.1}\\x = \frac{1 +- 7}{2} \\\\x' =4\\x'' = -3$