Question

x^2+9x-10=0 (me ajudeeeem)

Answer 1

x²+9x-10=0

a=1 b=9 c=-10

____________

Δ= b²-4.a.c

Δ= 9²-4.1.(-10)

Δ= 81+40

Δ= 121

_______________

x= -b+-√Δ/2a            √Δ=√121=11

x'= -9+11/2 = 2/2= 1

x"= -9-11/2 = -20/2 = -10