Question

- x ^ 2 + 6x - 10 = 0

Answer 1

Resposta:

Bhaskara

$-x^{2} +6x-10=0\\ \\ coeficientes:\\ \\ a=-1;b=6;c=-10\\ \\ delta=b^{2} -4.a.c\\ \\ delta=6^{2} -4.(-1).(-10)\\ \\ delta=36-(+40)=40-36=4\\ \\ delta=4\\ \\ \\ x=\frac{-b+-\sqrt{delta} }{2.a} \\ \\ x=\frac{-6+-\sqrt{4} }{-2} \\ \\ x=\frac{-6+-2}{-2} \\ \\ x'=\frac{-6+2}{-2}=\frac{-4}{-2} =+2\\ \\ x''=\frac{-6-2}{-2}= \frac{-8}{-2} =+4\\ \\ \\ S\left \{ {{2,4} {}} \}$