Question

x^2 - 5x + 8 = 0
com fórmula de bhaskara

Answer 1

Δ=b²-4*a*c
Δ=-5² -4*1*8
Δ=25-32
Δ=-7

$x=$$\frac{-b+- \sqrt{delta} }{2a}$

$x= \frac{-(-5) +- \sqrt{7} }{2}$

x1
$x1= \frac{-5+ \sqrt{7} }{2}$

x2
$x2= \frac{ -\sqrt{7}- 5}{2}$

onde x1 e x2 são as possibilidades