Question

X^2-4x+3=0

Eu queria saber no metado -B + ou - √b^2-4.(a).(c)

Answer 1

${x}^{2} - 4x + 3 = 0 \\ a = 1\\ b = ( - 4) \\ c = 3 \\ x = \frac{- b± \sqrt{{b}^{2} - 4 \times a \times c}}{2 \times a} \\ x = \frac{- ( - 4)± \sqrt{ {( - 4)}^{2} - 4 \times 1 \times 3 } }{2 \times 1} \\ x = \frac{ 4± \sqrt{16 - 12} }{2} \\ x = \frac{4± \sqrt{4} }{2} \\ x = \frac{4±2}{2} \\ x = \frac{4 + 2}{2} \: \: \: \: \: x = 3 \\ x = \frac{4 - 2}{2} \: \: \: \: \: x = 1 \\ \\ resposta = (3 \: e \: 1)$