Question

-x^2+4x=0 me ajudem pf

Answer 1

-x²+4x=0
a=-1; b=4; c=0
-4 +- √(4²- 4*-1*0) / 2*-1
-4 +- √(16- 0) / -2
-4 +- √(16) / -2
(-4+-4) / -2

X'= -4 +4 / -2 = 0 / 2 = 0
X"= -4 -4 / -2 = -8 / -2 = 4

X' = 0
X" = 4

Answer 2

Olá :)

-x² + 4x = 0

Δ= 4² - 4 . (-1) . 0
Δ= 16 - 0
Δ= 16

x = $\frac{-4 +- \sqrt{16} }{2}$

$x_{1}$ = $\frac{-4+4}{2}$
$x_{1}$ = $\frac{0}{2}$
$x_{1}$ = 0

$x_{2}$ = $\frac{-4-4}{2}$
$x_{2}$ = $\frac{-8}{2}$
$x_{2}$ = -4

S = (-4, 0)

Espero ter ajudado.
Boa Sorte!