Question

x'2-2x+1=0
x'2+7x+12=0

me ajudem pfv

Answer 1

x2 - 2x + 1 = 0

∆ = 2^2 - 4

∆ = 4 - 4

∆ = 0

x = - b / 2a

x = 2 / 2

x = 1

x2 + 7x + 12 = 0

∆ = 7^2 - 4• 12

∆ = 49 - 48

∆ = 1

X1 = ( - 7 + 1 ) / 2

X1 = - 6 / 2

X1 = - 3

X2 = ( - 7 - 1 ) / 2

X2 = - 8 / 2

X2 = - 4