Question

(x+2)²+(x+3)²+(x+4)²+(x+5)²

Answer 1

Opa

(x+2)² + (x+3)² + (x+4)² + (x+5)² =              
(x² + 2.x.2 + 2²) + (x² + 2.x.3 + 3³) + (x² + 2.x.4 +4²) + ( x² + 2.x.5 + 5²) =
x² + 4x + 4 + x² + 6x + 9 + x² + 8x + 16 + x² + 10x + 25 =
x² + x² + x² + x² + 4x + 6x + 8x + 10x + 4 + 9 + 16 + 25 =
4x² + 28x + 54

Espero ter ajudado.

Answer 2

Hola! 
(x+2)²+(x+3)²+(x+4)²+(x+5)²= 

$(x+2)^2+(x+3)^2+(x+4)^2+(x+5)^2= \\ \\ (x^2+4x+4)+(x^2+6x+9)+(x^2+8x+16)+(x^2+10x+25)= \\ \\ \boxed { \boxed{ 4x^2+28x+54 } }$