Question

(x- 2)^2+ (x + 1 )^2 = 5 ajudaaaaaa

Answer 1

(x- 2)^2+ (x + 1 )^2 = 5 // [(X - 2) . (X - 2)] + [(x + 1 ) . (x + 1 )] = 5 // [X^2 - 2x - 2x + 4] + [x^2 + x + x + 1^2] = 5 // X^2 - 4x + 4 + x^2 + 2x + 1 = 5 // 2x^2 - 2x + 5 = 5 // 2x^2 - 2x = 5 - 5 // 2x^2 - 2x = 0. Delta = 4 // Bhaskara X1= 1 x2=0

Answer 2

(x-2) ^2 + (x+1)^2 = 5 
(tecnica do chuveirinho)
$x^{2}$  - 2x - 2x + 4 + $x^{2}$ + x + x + 1 
2 $x^{2}$ - 4x + 2x + 5 = 5
2 $x^{2}$ - 2x = 5 - 5
$x^{2}$ - 2x = 0
(bhaskara)
x = 1 ou $\frac{1}{2}$