Question

(x-2)²+4x=4


x.(x+2)=4x


3.(x-2)²=12

Answer 1

(x-2)²+4x = 4

x² - 4x + 4 + 4x = 4

x² + 4 = 4

x² = 4 - 4

x² = 0 ---> x = 0

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x.(x+2) = 4x

x² + 2x = 4x

x² + 2x - 4x = 0

x² - 2x = 0

x(x - 2) = 0

x = 0

x-2= 0 --> x = 2

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3.(x-2)² = 12

3(x² - 4x + 4) = 12

x² - 4x + 4 = 12/3

x² - 4x + 4 = 4

x² - 4x + 4 - 4 = 0

x² - 4x = 0

x(x - 4) = 0

x = 0

x-4 = 0--> x = 4