Question

x^2+0x-9=0 Ajudem (Método Bhaskara)​

Answer 1

x²+0x+9 =0

x²+9=0

x²=9

x=±√9

x=±3

{3,-3}

Answer 2

$\mathtt{ {x}^{2} \: + \: 0x \: - \: 9 \: = \: 0}$

$\mathtt{a \: = \: 1}$

$\mathtt{b \: = \: 0}$

$\mathtt{c \: = \: - 9}$

∆ = b² - 4.a.c

∆ = 0² - 4.1.(-9)

∆ = 0 - 4 . -9

∆ = 0 + 36

∆ = 36

$\mathtt{x \: = \: \frac{ - b ± \: \sqrt{ {b}^{2}\: - \: 4ac}}{2a}}$

x = -b ± √∆ / 2a

x = -0 ± √36 / 2 . 1

x = -0 ± 6 / 2

x = ±6 / 2

x' = +6 / 2 = x' = +3

x'' = -6 / 2 = x'' = -3