Question

x=2,0t + t². quando x=60

Answer 1

60 = 2t + t² -> 0 = t² + 2t - 60 (bhaskara)
Δ = 2² - 4 . -60 . 1
Δ = 4 + 240 = 244
x = (-2 +- √244)/2
x = (-2 +- √2² . 61)/2
x = (-2 +- 2√61)/2