Question

) (x + 10). (x + 10) =
(y-5). (y-5) =
(x+3)( x-3)
Il​

Answer 1

Primeira

$\sf (x + 10)\cdot (x + 10)$

$\sf = {x}^{2} + 10x + 10x + 100$

$\red{\sf = {x}^{2} + 20x + 100}$

Segunda

$\sf (y - 5)\cdot (y - 5)$

$\sf = {y}^{2} - 5y - 5y + 25$

$\red{\sf = {y}^{2} - 10y + 25}$

Terceira

$(\sf x + 3)\cdot (x - 3)$

$\sf = {x}^{2} - 3x + 3x - 9$

$\red{\sf = {x}^{2} - 9}$