Question

x+1/x-8+x+1/x=1 me ajudem pfv

Answer 1

Resposta:

$\frac{x+1}{x-8} +\frac{x+1}{x} =1 \implies \frac{x(x+1)}{x(x-8)} + \frac{(x+1)(x-8)}{x(x-8)}=1 \implies \frac{(x+1)(2x-8)}{x(x-8)}=1 \implies (x+1)(2x-8)= x(x-8) \implies 2x^2-8x+2x-8 = x^2-8x \therefore x^2+2x-8 = 0 \implies (x+4)(x-2) = 0 \therefore x=2 \vee x=-4$

Explicação passo-a-passo: