Question

X+1 /x-8 + x+1/x = 1/1 ajudem pfv

Answer 1

$\frac{x+1}{x-8} + \frac{x+1}{x} = \frac{1}{1}\\ mmc = x(x-8) = x^2-8x\\\\Vamos- dividir os numeradores:\\x^2-8x : x-8= -x \\-x^2+8x\\ 0\\R= -x\\-----------------\\Segundo numerador:\\x^2-8x : x = -x+8\\-x^2 \\-8x\\\\+8x\\0\\R = -x+8\\----------------$

$Agora-vamos-responder:\\\\\frac{x+1}{x-8} + \frac{x+1}{x} = \frac{1}{1}\\\\\frac{(x+1)(-x)+(x+1)(-x+8)}{x^2-8x} = \frac{1(x^2-8x)}{x^2-8x} \\-x^2-x+(-x^2+8x-x+8) = x^2-8x\\\\-x^2-x-x^2+8x-x+8 = x^2-8x\\-2x^2-2x+8x+8 = x^2-8x\\-2x^2+6x+8 = x^2-8x\\-2x^2-x^2+6x+8x= -8\\-3x^2+14x+8=0\\\\Chegamos-em-uma-equa.2\º\\\\-3x^2+14x+8=0$