Question

(x+1)(x-3)=-3 ajude plz

Answer 1

(x+1)(x-3)=-3
x²-3x+x-3=-3
x²-2x=0
a=1
b=-2
c=0

Δ=b²-4ac
Δ=(-2)²-4×1×0
Δ=4

X=(-b+√Δ)/2a
X=(-(-2)+√4)/2×1
X'=(2+2)/2
X'=4/2=2

X"=(2-2)/2
X"=0/2=0

Answer 2

(x + 1)(x - 3) = - 3
x² - 3x + x - 3 = - 3
x² - 2x - 3 + 3 = 0
x² - 2x = 0
x (x - 2 ) = 0
x' = 0
x" = 2

S = { 0 e 2 }