Question

(x + 1) . (x - 2) . (x - 3) como calcular

Answer 1

(x+1)(x-2)(x-3)

= [ x*x+x*(-2)+1*x+1*(-2) ](x-3)

= (x^2-2x+x-2)(x-3)

= (x^2-x-2)(x-3)

= (x-3)(x^2-x-2)

= [ x*x^2+x*(-x)+x*(-2)-3x^2+3x-6)]

= x^3-4x^2+x-6