Question

(x-1).(x+1)+(x+2)²=4 Alguém me ajuda, por favor!!!

Answer 1

$(x-1).(x+1)+(x+2)^2=4\\\\(x-1).(x+1)+(x+2)(x+2)=4\\\\(\; x*x+1*x-1*x +1*(-1) \;)+(\; x*x+2*x+2*x 2*2) \;)=4\\\\(x^2-1)+(x^2+4x+4)=4\\\\2x^2+4x+3=4\\\\2x^2+4x-1=0\\\\Bhaskara:\\\\\Delta=4^2-4*2*(-1) = 16 + 8 = 24\\\\x=\frac{-4\pm\sqrt{24}} {2*2} \\\\x=\frac{-4\pm2\sqrt{6}} {4} \\\\x_1=\frac{-4+2\sqrt{6}}{4} =-1+\frac{\sqrt{6}}{2}\\\\x_2=\frac{-4-2\sqrt{6}}{4} =-1-\frac{\sqrt{6}}{2}$