Question

(x+1)^2 = x^2 + (√7)^2 ajudeem !!!??

Answer 1

(x+1)² = x²+( $\sqrt{7}$ )²=
(x+1)(x+1) = x² ( $\sqrt{7} ) ( \sqrt{7} )$ 
x²+x+x+1   = x² +( $\sqrt{49} )$
x² + 2x +1  = x² +7 
x² -x² +2x=7-1
     2x= 6
  x=6/2= 3