Question

x- 1=1
6 3  2

x+x=8
    3

x-1=x
3    4 

resolva 

Answer 1

1)

$\dfrac{x}{6} - \dfrac{1}{3} = \dfrac{1}{2} \\ \\ \\ \dfrac{x}{6} - \dfrac{1}{3} - \dfrac{1}{2} = 0 \\ \\ \\ \dfrac{x - 2 - 3 }{6} = 0 \\ \\ \\ \dfrac{x - 5 }{6} \\ \\ \\ x - 5 = 0 \\ \\ \\ x = 5$

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2)

$x + \dfrac{x}{3} = 8 \\ \\ \\ x + \dfrac{x}{3} - 8 = 0 \\ \\ \\ \dfrac{3x + x - 24 }{3} =0 \\ \\ \\ \dfrac{4x - 24 }{3} =0 \\ \\ \\ 4x - 24 = 0 \\ \\ \\ 4x = 24 \\ \\ \\ x = \dfrac{24}{4} \\ \\ \\ x =6$

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3)

$\dfrac{x}{3} - \dfrac{1}{4} = x \\ \\ \\ \dfrac{x}{3} - \dfrac{1}{4} - x = 0 \\ \\ \\ \dfrac{4x - 3 - 12x}{12} =0 \\ \\ \\ \dfrac{-8x - 3}{12} = 0 \\ \\ \\ -8x -3 = 0 (-1) \\ \\ \\ 8x + 3 = 0 \\ \\ \\ 8x = -3 \\ \\ \\ x = -\dfrac{3}{8}$