Question

Vx-+1=2

V4x+3=V2x-3


preciso das resposta urgente ​

Answer 1

$\Large\boxed{\begin{array}{l}\sf\sqrt{x-(+1)}=2\\\sf\sqrt{x-1}=2\\\sf(\sqrt{x-1})^2=2^2\\\sf x-1=4\\\sf x=4+1\\\sf x=5\\\underline{\boldsymbol{verificac_{\!\!,}\tilde ao\!:}}\\\sf \sqrt{5-+(1)}=\sqrt{5-1}=\sqrt{4}=2\\\sf como~2=2~ent\tilde ao\,est\acute a\,correta.\end{array}}$

$\Large\boxed{\begin{array}{l}\sf\sqrt{4x+3}=\sqrt{2x-3}\\\sf 4x+3=2x-3\\\sf 4x-2x=-3-3\\\sf 2x=-6\\\sf x=-\dfrac{6}{2}\\\\\sf x=-3\\\underline{\boldsymbol{verificac_{\!\!,}\tilde ao\!:}}\\\sf \sqrt{4\cdot(-3)+3}=\sqrt{-12+3}=\sqrt{-9}\not\in\mathbb{R}\\\sf \sqrt{2\cdot(-3)-3}=\sqrt{-6-3}=\sqrt{-9}\not\in\mathbb{R}\\\sf logo\\\sf S=\bigg\{\bigg\}\end{array}}$