Question

Victor Ajuda Aí nmrnmr

Answer 1

6)

$A = \sqrt{ \sqrt{6} - 2 } \times \sqrt{ 2 + \sqrt{6} } \\ \\ {A}^{2} = ( \sqrt{ \sqrt{6} - 2} \times \sqrt{2 + \sqrt{6} } \: ) {}^{2} \\ \\ {A}^{2} = ( \sqrt{6 } - 2)\times( 2 + \sqrt{6} ) \\ \\ {A}^{2} = + 2 \sqrt{6} + \sqrt{36} - 4 - 2 \sqrt{6} \\ \\ {A}^{2} = \sqrt{36} - 4 \\ \\ {A}^{2} = 6 - 4 \\ \\ {A}^{2} = 2$

Letra b) 2

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