Question

Vértice e 0 da função y=x²-2x+4

Answer 1

Vertice

$x^2-2x+4\\ \Delta=b^2-4.a.c\\ \Delta=(-2)^2-4.1.4\\ \Delta=4-16\\ \Delta=-12 \ \ \ \nexists \ x \in \mathbb{R}\\ VY=\displaystyle\frac{-\Delta}{4.a}=\frac{-(-12)}{4.1}=\frac{12}{4}=3\\ VX=\displaystyle\frac{-b}{2.a}=\frac{-(-2)}{2.1}=\frac{2)}{2}=1$

Não existe os 0 da função

Answer 2

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