Question

vertice de (x+3)(x-5) vlw

Answer 1

Aplicando distributiva:
x²-5x+3x-15=0
x²-2x-15=0

Fórmula para achar o vértice:
Achar o x do vértice:
Xv=-b/2a
Xv= -(-2)/2.1
Xv=2/2
Xv=1

Achar o y do vértice:
Yv=-Delta/4.a
Yv=-(b²-4.a.c)/4.a
Yv=-(-2²-4.1.(-15)/4.1
Yv=-(4+60)/4
Yv=-64/4
Yv= -16

Vértices (1;-16)

:D