Matemática, perguntado por reppinsophia, 4 meses atrás

vértice da função y = x² + x + 1

Soluções para a tarefa

Respondido por CyberKirito
0

\Large\boxed{\begin{array}{l}\sf y=x^2+x+1\\\sf\Delta=b^2-4ac\\\sf\Delta=1^2-4\cdot1\cdot1\\\sf\Delta=1-4\\\sf\Delta=-3\\\sf x_V=-\dfrac{b}{2a}\\\\\sf x_V=-\dfrac{1}{2\cdot1}\\\\\sf x_V=-\dfrac{1}{2}\\\\\sf y_V=-\dfrac{\Delta}{4a}\\\\\sf y_V=-\dfrac{-3}{4\cdot1}\\\\\sf y_V=\dfrac{3}{4}\\\sf V(x_V,y_V)\\\\\sf V\bigg(\!\!\!-\dfrac{1}{2},\dfrac{3}{4}\bigg)\end{array}}

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