Question

vcs poden resolver isso pra mim

Answer 1

Oi vc pode me ajudar

Answer 2

Aplicando o Teorema de Tales:

$\frac{x}{x+2} = \frac{x-3}{x-2}\\\\(x-2)x} = (x-3)(x+2)\\x^2-2x = x^2-x-6\\x^2-2x -x^2+x= -6\\-2x +x= -6\\-x = -6\\\\\boxed{x = 6}$