Question

Vamos utilizar o fator comum em evidencia,para resolver as equacoes de segundo grau a seguir: a)3x²-x=0 b)2x²+23x=0 c)5x²-56x=0

Answer 1

Resposta:

a)3x²-x=0

= 3x(x-1/3) = 0

=> x-1/3 = 0

<=> x = 1/3

S:{0,1/3}

b)2x²+23x=0

2x(x+23/2) = 0

<=> x + 23/2 = 0

<=> x = -23/2

S:{-23/2 , 0}

c)5x²-56x=0

5x(x-56/5) = 0

<=> x - 56/5 = 0

<=> x = 56/5

S:{0,56/5}