Question

Vamos! quem pode calcular a integral $\int\limits^2_1 {(1+2y) ^{2} } \, dy$

Answer 1

$\int\limits^2_1 { (1+2y)^{2} } \, dy = \int\limits^2_1 { 1 + 4y + 4y^2 } \, dy = y + 2y^2 + \frac{4y^3}{3} \left \right|_{1}^{2} = 49/3$