Question

vamos lá
a) 8
b) 4
c) 10
d) -11
e) -8

Answer 1

$\\ f(x) = \frac{4}{x} +5x^2+8 \\ \\ f(x) = 4*x^-^1+5x^2+8 \\ \\ f'(x) = -1*4*x^-^2+2*5x^1+0 \\ \\ f'(x) = -4x^-^2+10x \\ \\ f'(x) = \frac{-4}{x^2} +10x \\ \\ f'( \frac{1}{2} )= \frac{-4}{( \frac{1}{2})^2 } +10* \frac{1}{2} \\ \\ f'( \frac{1}{2} )= \frac{-4}{\frac{1}{4} } +5 \\ \\ f'( \frac{1}{2} ) = -4*4 + 5 \\ \\ f'( \frac{1}{2} ) -16+5 =-11$