Question

Vamos calcular: a) (-10a^2b)^2= b)(-1/5m^2n)^2= c)(0,5ab^2)^2= d)(-am^5x^3)^4= e)(2/3x^3 y^2)^2= f)(a^2c^3)^7= g)(-x^2 y^2/5)^2= I)(0,1p^5)^2= me ajudar

Answer 1

Resposta:

$\sf \text{Leia abaixo}$

Explicação passo-a-passo:

$\sf a)\: (-10a^2b)^2 = 100a^4b^2$

$\sf b)\: (-\dfrac{1}{5}m^2n)^2 = \dfrac{1}{25}m^4n^2$

$\sf c)\: (0,5ab^2)^2 = 0,25a^2b^4$

$\sf d)\: (-am^5x^3)^4 = a^4m^{20}x^{12}$

$\sf e)\: (\dfrac{2}{3}x^3y^2)^2 = \dfrac{4}{9}x^6y^4$

$\sf f)\: (a^2c^3)^7 = a^{14}c^{21}$

$\sf g)\: (-x^2y^\frac{2}{5})^2 = x^4y^\frac{4}{5}$

$\sf i)\: (0,1p^5)^2 = 0,01p^{10}$

Answer 2

Oie, Td Bom?!

a)

$( - 10a {}^{2} b) {}^{2} = 100a {}^{4} b {}^{2}$

b)

$( - \frac{1}{5} m {}^{2} n) {}^{2} = \frac{1}{25} m {}^{4} n {}^{2}$

c)

$(0,5ab {}^{2} ) {}^{2} = 0,25a {}^{2} b {}^{4}$

d)

$( - am {}^{5} x {}^{3} ) {}^{4} = a {}^{4} m {}^{20} x {}^{12}$

e)

$( \frac{2}{3} x {}^{3} y {}^{2} ) {}^{2} = \frac{4}{9} x {}^{6} y {}^{4}$

f)

$(a {}^{2} c {}^{3} ) {}^{7} = a {}^{14} c {}^{21}$

g)

$( - x {}^{2}y {}^{ \frac{2}{5} } ) {}^{2} = x {}^{4} y {}^{ \frac{4}{5} }$

i)

$(0,1p {}^{5} ) {}^{2} = 0,01p {}^{10}$

Att. Makaveli1996