Matemática, perguntado por contabloqueada1234, 11 meses atrás

valendo 70 pontos
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Anexos:

Soluções para a tarefa

Respondido por Usuário anônimo
0

Explicação passo-a-passo:

1)

a) \sf 2^3\div2^2=2^{3-2}=\red{2^1}

b) \sf 4^4\div4^5=4^{4-5}=\red{4^{-1}}

c) \sf 3^6\div3^2=3^{6-2}=\red{3^4}

d) \sf 8^3\div8^4=8^{3-4}=\red{8^{-1}}

e) \sf 9^7\div9^2=9^{7-2}=\red{9^5}

f)

\sf 5^7\div5^2\div5^8\div5^6

\sf =5^{7-2}\div5^{8-6}

\sf =5^5\div5^2

\sf =5^{5-2}

\sf =\red{5^3}

g)

\sf 6^9\div6^3\div6^0\div6^5

\sf =6^{9-3}\div6^{0-5}

\sf =6^6\div6^{-5}

\sf =6^{6+5}

\sf =\red{6^{11}}

h)

\sf 7^5\div7^9\div7^4\div7^0

\sf =7^{5-9}\div7^{4-0}

\sf =7^{-4}\div7^{4}

\sf =7^{-4-4}

\sf =\red{7^{-8}}

2)

a)

\sf 5^4\div5^2\times5^3\div5^9

\sf =5^{4-2}\times5^{3-9}

\sf =5^2\times5^{-6}

\sf =5^{2-6}

\sf =\red{5^{-4}}

b)

\sf 8^7\times8^9\div8^3\times8^4

\sf =8^{7+9}\div8^{3+4}

\sf =8^{16}\div8^{7}

\sf =8^{16-7}

\sf =\red{8^9}

c)

\sf 9^5\div9^2\div9^5\times9^4

\sf =9^{5-2}\div9^{5+4}

\sf =9^3\div9^9

\sf =9^{3-9}

\sf =\red{9^{-6}}

d)

\sf 4^3\div4^2\div4^9\div4^{10}

\sf =4^{3-2}\div4^{9-10}

\sf =4^1\div4^{-1}

\sf =4^{1+1}

\sf =\red{4^2}

e)

\sf 9^6\times9^3\div9^5\times9^2

\sf =9^{6+3}\div9^{5+2}

\sf =9^9\div9^7

\sf =9^{9-7}

\sf =\red{9^{2}}

Respondido por pietroalmeidasilva18
0

1)

a)  

b)  

c)  

d)  

e

a)  

b)  

c)  

d)  

e)  

f)

g)

h)

2)

a)

b)

c)

d)

e)

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