Question

Valendo 27 pontos urgente.
Dadas as matrizes A=(2 3 8 1 -4 0) B= (4 5 -9 6 2 7) C=( 2 0 8 6 -4 -10)
calcule A+B 2.A-B 3.A-2.Ct

Resolva as equações matriciais A( -7 2 1 6 4-3)+x=( 5 3 -1 1 0 2) B (4 3 0 5) +2.x= (14 9 -2 13) ?

Answer 1

$1) A= \left[\begin{array}{ccc}2&3&8\\1&-4&0\\\end{array}\right] e ,B= \left[\begin{array}{ccc}4&5&-9\\6&2&7\\\end{array}\right] e, C= \left[\begin{array}{ccc}2&0\\8&6\\-4&-10\end{array}\right] \\\\>A+B= \left[\begin{array}{ccc}6&8&-1\\7&-2&7\\\end{array}\right]\\\\>2*(A-B)=2* \left[\begin{array}{ccc}-2&-2&17\\-5&-6&-7\\\end{array}\right] = \left[\begin{array}{ccc}-4&-4&34\\-10&-12&-14\\\end{array}\right] \\\\\left[\begin{array}{ccc}2&0\\8&6\\-4&-10\end{array}\right]$
     $\\\\>3*\left[\begin{array}{ccc}2&3&8\\1&-4&0\\\end{array}\right]-2*\left[\begin{array}{ccc}0&6&-10\\2&8&-4\\\end{array}\right] =$ $\left[\begin{array} {ccc}6&9&24\\3&-12&0\\\end{array}\right]-\left[\begin{array}{ccc}0&12&-20\\4&16&-8\\\end{array}\right]$ $= \left[\begin{array}{ccc}6&-3&44\\-1&-28&8\\\end{array}\right]$



$2)\\A) \left[\begin{array}{ccc}-7&2&1\\6&4&-3\\\end{array}\right]+x= \left[\begin{array}{ccc}5&3&-1\\1&0&2\\\end{array}\right] \\\\x=\left[\begin{array}{ccc}5&3&-1\\1&0&2\\\end{array}\right]-\left[\begin{array}{ccc}-7&2&1\\6&4&-3\\\end{array}\right] = \left[\begin{array}{ccc}12&1&-2\\-5&-4&5\\\end{array}\right]$
$B) \left[\begin{array}{ccc}4&3\\0&5\\\end{array}\right]+2x= \left[\begin{array}{ccc}14&9\\-2&13\\\end{array}\right]=>2x=\left[\begin{array}{ccc}14&9\\-2&13\\\end{array}\right]- \left[\begin{array}{ccc}4&3\\0&5\\\end{array}\right] =>$$2x=\left[\begin{array}{ccc}10&6\\-2&8\\\end{array}\right]=>x=\left[\begin{array}{ccc}5&3\\-1&4\\\end{array}\right]$ :.