Question

VALENDO 20 PONTOS!!!
Sendo A = $\left[\begin{array}{ccc}3&2&\\5&1&\\&&\end{array}\right]$ E B = $\left[\begin{array}{ccc}3&-1&\\2&0&\\&&\end{array}\right]$, a matriz resultante do produto A.B é:
POR FAVOR COM CÁLCULOS


a) $\left[\begin{array}{ccc}33&17&\\-3&-5&\\&&\end{array}\right]$

b) $\left[\begin{array}{ccc}13&-3&\\17&-5&\\&&\end{array}\right]$

c) $\left[\begin{array}{ccc}10&-5&\\11&-6&\\&&\end{array}\right]$

d) $\left[\begin{array}{ccc}10&11&\\-5&-6&\\&&\end{array}\right]$

e) $\left[\begin{array}{ccc}36&0&\\30&0&\\&&\end{array}\right]$

Answer 1

Explicação passo-a-passo:

$\sf A\cdot B=\Big[\begin{array}{cc} \sf 3 & \sf 2 \\ \sf 5 & \sf 1 \end{array}\Big]\cdot\Big[\begin{array}{cc} \sf 3 & \sf -1 \\ \sf 2 & \sf 0 \end{array}\Big]$

$\sf A\cdot B=\Big[\begin{array}{cc} \sf 3\cdot3+2\cdot2 & \sf 3\cdot(-1)+2\cdot0 \\ \sf 5\cdot3+1\cdot2 & \sf 5\cdot(-1)+1\cdot0 \end{array}\Big]$

$\sf A\cdot B=\Big[\begin{array}{cc} \sf 9+4 & \sf -3+0 \\ \sf 15+2 & \sf -5+0 \end{array}\Big]$

$\sf A\cdot B=\Big[\begin{array}{cc} \sf 13 & \sf -3 \\ \sf 17 & \sf -5 \end{array}\Big]$

Letra B

Answer 2

Resposta:

letra b

Explicação passo a passo: