Question

utilize as propriedades da potenciaçao e calcule as potencias a seguir:
a. 2².2^5 =
b. (3³ )² =
c. (4 . 3)² =
d. (3/4)^4 =
e. 32^1/5 =
f. 1033^0 =
g. 1^1/3 =
h. 20^15 : 20^13 =
i. a^12 . a^5 =
j. 5-^4 = (1/5)^4 =
Por Favor Me Ajude vai ganhar 15 pontos please please

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{a) \ 2^2 \cdot 2^5 = 2^{(2+5)} = 2^7 = 128}\\\\\mathsf{b) \ (3^3)^2 = 3^{3 \cdot 2} = 3^6 = 729}\\\\\mathsf{c) \ (4 \cdot 3)^2 = 12^2 = 144}\\\\\mathsf{d) \ \left(\dfrac{3}{4}\right)^4 = \left(\dfrac{3^4}{4^4}\right)=\left(\dfrac{81}{256}\right)}\\\\\mathsf{ e) \ 32^{1/5} = \sqrt[5]{32}=2 }}\\\\\mathsf{f) \ 1033^0 = 1}\\\\\mathsf{g) \ 1^{1/3} = 1}\\\\\mathsf{h) \ \dfrac{20^{15}}{20^{13}} =20^{(15-13)} = 20^2 = 400}\\\\\mathsf{i) \ a^{12} \cdot a^5 = a^{(12+5)} = a}^{17}}$

$\mathsf{j) \ 5^{(-4)} = \left(\dfrac{1}{5}\right)^4 = \dfrac{1}{625} }$