utilize a formula de bhaskara para resolver as equaçoes do 2° grau?
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a)x²-7x+10=0
a=1
b=-7
c=10
∆=(-7)²-4*1*10
∆=49-40
∆=9
x=-(-7)±√9/2
x=7±3/2
x1=7-3/2
x1=2
x2=7+3/2
x2=5
S={2,5}
b)7x²+x+1=0
a=7
b=1
c=1
∆=1²-4*7*1
∆=1-28
∆=-27
x=-1±√-27/14
X=IR
c)x²-6x+9=0
a=1
b=-6
c=9
∆=(-6)²-4*1*9
∆=36-36
∆=0
x=-(-6)±√0/2
X=3
S={3}
d)25x²-20x+4=0
a=25
b=-20
c=4
∆=(-20)²-4*25*4
∆=400-400
∆=0
x=-(-20)±√0/2*25
x=20±0/50
x=2/5
S={2/5}
a=1
b=-7
c=10
∆=(-7)²-4*1*10
∆=49-40
∆=9
x=-(-7)±√9/2
x=7±3/2
x1=7-3/2
x1=2
x2=7+3/2
x2=5
S={2,5}
b)7x²+x+1=0
a=7
b=1
c=1
∆=1²-4*7*1
∆=1-28
∆=-27
x=-1±√-27/14
X=IR
c)x²-6x+9=0
a=1
b=-6
c=9
∆=(-6)²-4*1*9
∆=36-36
∆=0
x=-(-6)±√0/2
X=3
S={3}
d)25x²-20x+4=0
a=25
b=-20
c=4
∆=(-20)²-4*25*4
∆=400-400
∆=0
x=-(-20)±√0/2*25
x=20±0/50
x=2/5
S={2/5}
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