Question

utilizando o teorema de pitágoras determine o valor de x nos triângulos abaixo​

Answer 1

Explicação passo-a-passo:

a)

$\sf x^2+5^2=11^2$

$\sf x^2+25=121$

$\sf x^2=121-25$

$\sf x^2=96$

$\sf x=\sqrt{96}$

$\sf \red{x=4\sqrt{6}}$

b)

$\sf x^2=21^2+28^2$

$\sf x^2=441+784$

$\sf x^2=1225$

$\sf x=\sqrt{1225}$

$\sf \red{x=35}$

c)

$\sf x^2=24^2+32^2$

$\sf x^2=576+1024$

$\sf x^2=1600$

$\sf x=\sqrt{1600}$

$\sf \red{x=40}$