Question

Utilizando o Teorema de Pitagoras, determine o valor de X nos triangulos retangulos:

Answer 1

20² = (3x)² + (4x)² 
400= 9x² + 16x²
400= 25x²
x² = $\frac{400}{25}$
x²= $\frac{80}{5}$
x²= 16
x= $\sqrt{16}$
x= 4


3$\sqrt{52}$ = 62 + x²
45  = 36 + x²
45 - 36 = x²
9= x²
$\sqrt{9}$ = x
x=3