Question

Utilizando o teorema de Pitágoras, determine o valor de "X" nos triângulos retângulos ?

Answer 1

a)
$3 {}^{2} + 4 {}^{2} = x {}^{2} \\ x = 5$
b)
$6 {}^{2} + x {}^{2} = (3 \sqrt{5} ) {}^{2} \\ x {}^{2} = 45 - 36 \\ x = 3$
c)
$\sqrt{7} {}^{2} + x { {}^{} }^{2} = (x + 1) {}^{2} \\ x {}^{2} + 7 = x {}^{2} + 2x + 1 \\ 6 = 2x \\ x = 3$
d)
$x {}^{2} + x {}^{2} = 9 \\ 2x {}^{2} = 9 \\ x = \frac{ \sqrt{9} }{ \sqrt{2} } \\ x = \frac{3 \sqrt{2} }{2}$
e)
$x {}^{2} + 576 = 625 \\ x {}^{2} = 49 \\ x = 7$
f)
$784 + 441 = x { }^{2} \\ 1225 = x {}^{2} \\ x = 35$
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