Question

Utilizando o teorema de pitagoras, determine o valor de x nos triângulos retângulos:

Answer 1

e) x² = 8² + 6²
x² = 64 + 36
x² = 100
x = √100
x = 10

f)  25² = x² + 7²
625 = x² + 49
625 - 49 = x²
x² = 576
x = √576
x = 24

g) (√7)² = x² + 2²
7 = x² + 4
7 - 4 = x²
x² = 3
x = √3

h) 14² = x² + (5√3)²
196 = x² + 25(√3)²
196 = x² + 25 . 3
196 = x² + 75
196 - 75 = x²
x² = 121
x = √121
x = 11

Answer 2

e)
hipotenusa⇒x
catetos⇒6 e 8

x²=6²+8²
x²=36+64
x²=100
x=√100
x=10

f)
hipotenusa⇒25
catetos⇒7 e x
25²=7²+x²
x²=625-49
x²=576
x=√576
x=24

g)
hipotenusa⇒√7
catetos⇒2 e x

(√7)²=2²+x²
x²=7-4
x²=3
x=√3

h)
hipotenusa⇒14
catetos⇒x e 5√3

14²=x²+(5√3)²
196=x²+25.3
x²=196-75
x²=121
x=√121
x=11