Question

utilizando o seno dos ângulos indicados, encontre o valor de x​

Answer 1

a)

$\sin(30\degree)=\frac{13}{x}$

$\frac{1}{2}=\frac{13}{x}$

$x=2.13$

$\boxed{x=26}$

b)

$\sin(45\degree)=\frac{6\sqrt{2}}{x}$

$\frac{\sqrt{2}}{2}=\frac{6\sqrt{2}}{x}$

$\frac{\cancel{\sqrt{2}}}{2}=\frac{6\cancel{\sqrt{2}}}{x}$

$x=2.6$

$\boxed{ x=12}$

c)

$\sin(60\degree)=\frac{x}{4\sqrt{3}}$

$\frac{\sqrt{3}}{2}=\frac{x}{4\sqrt{3}}$

$2x=4\sqrt{3}.\sqrt{3}$

$2x=4.3$

$x=\frac{12}{2}$

$\boxed{x=6}$

d)

$\sin(60\degree)=\frac{x}{14}$

$\frac{\sqrt{3}}{2}=\frac{x}{14}$

$2x=14\sqrt{3}$

$x=\frac{14\sqrt{3}}{2}$

$\boxed{x=7\sqrt{3}}$

e)

$\sin(x)=\frac{\sqrt{3}}{2\sqrt{3}}$

$\sin(x)=\frac{\cancel{\sqrt{3}}}{2\cancel{\sqrt{3}}}$

$\sin(x)=\frac{1}{2}$

$x=arc\sin(\frac{1}{2})$

$\boxed{x=30\degree}$

Answer 2

Resposta:

a) sen30º = 13/x

      1/2 = 13/x

        x = 13.2

         x = 26

b) sen45 = 6√2/x

√2/2 = 6√2/x

x.√2 = 2.6√2

x = 12

c) sen60= x / 4√3

      √3/2 = x / 4√3

          2x = √3.4√3

           2x = 4.3

            2x = 12

              x = 12/2

               x = 6

d) sen60 = x/14

       √3/2 = x/14

          2x = 14√3

           x = 14√3/2

           x = 7√3

e) senx = √3: 2√3

  senx = √3. (1/2√3)

  senx = 1/2

     x = 30º

Explicação passo-a-passo: