Question

utilizando bhaskara determine
${x}^{2} + x - 10 \: igual \: a \: zero$
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Answer 1

Resposta:

x' = [- 1 + (41)^(1/2)] / 2

x'' = [- 1 - (41)^(1/2)] / 2

Explicação passo-a-passo:

x^2 + x - 10 = 0

a = 1

b = 1

c = - 10

Formula de Bhaskara

x = [- b +- (b^2 - 4 * a * c)^(1/2)] / 2 * a

x = [- 1 +- (1^2 - 4 * 1 * (-10))^(1/2)] / 2 * 1

x = [- 1 +- (1 +40)^(1/2)] / 2

x' = [- 1 + (41)^(1/2)] / 2

x'' = [- 1 - (41)^(1/2)] / 2