Question

utilizando as razões trigonométricas calcule

Answer 1

Olá!

Considerando o tg de 60° = √3
sen 60° = √3 / 2
___________________________

tg 60° = h/50

√3/1 = h/50

h = 50√3

h = 50 . 1,7

h = 85 m

___________________________

sen 60° = 85/y

√3/2 = 85/y

y√3 = 170

y1,7 = 170

y = 100 m

___________________________

Abraços! ☢

Answer 2

Olá

Nós usaremos algumas identidades trigonométricas

$\boxed{\cos60^{\circ}=\dfrac{1}{2}}$

$\boxed{\tan60^{\circ}=\sqrt{3}}$

Usemos o cosseno para descobrir a hipotenusa

$\cos(x)=\dfrac{C.A}{HIP}\\\\\\ \cos60^{\circ}=\dfrac{50}{y}\\\\\\ \dfrac{1}{2}=\dfrac{50}{y}\\\\\\ \boxed{y = 100}$

Usemos a tangente, para descobrir o cateto oposto

$\tan(x)=\dfrac{C.O}{C.A}\\\\\\ \tan 60^{\circ}=\dfrac{h}{50}\\\\\\ \sqrt{3}=\dfrac{h}{50}\\\\\\ h=50\sqrt{3}\\\\\\ h = 50\cdot 1,7\\\\\\ \boxed{h=85}$

A hipotenusa mede 100m e o cateto oposto mede 85 metros