Question

Utilizando a formulada de Bhaskara resolva:3x (ao quadrado)=7x+1

Answer 1

3x² = 7x + 1
3x² - 7x - 1 = 0


delta = b² - 4.a.b

a = 3
b = -7
c = -1


delta = (-7)² - 4.3.(-1)
delta = 49 + 12
delta = 61

x = -b ± √delta/2.a

x = -(-7) ± √61/2.3

x = 7 ± √61/6

x = (7 + √61)/6

x = (7 - √61)/6


s={ (7 + √61)/6, (7 - √61)/6 }