Question

Utilizando a formula de bhaskara para resolver as equações do segundo grau x²+5x-24=0

Answer 1

Δb²-4.a.c
Δ5²-4.1.(-24)
Δ25+96
Δ√121
Δ= 11

-b+-√Δ/2

x' -5+11/2 = 3
x'' -5-11/2 = -8

Answer 2

Resolução, veja:

$x = -b~ +_{-}~\dfrac{ \sqrt{b^{2}-4~.~a~.~c}}{2~.~a}\\\\\\ x = -5~+_{-}~\dfrac{ \sqrt{5^{2}-4~.~1~.~(-24)}}{2~.~1}}\\\\\\ x = -5~+_{-}~\dfrac{ \sqrt{25+96}}{2}\\\\\\ x = -5~+_{-}~\dfrac{ \sqrt{121}}{2}}\\\\\\ x = -5~+_{-}~\dfrac{11}{2}\\\\\\ x' = \dfrac{-5+11}{2}\\\\\\ x' = \dfrac{6}{2}\\\\\\ \large\boxed{\boxed{x' = 3.}}\\\\\\ x'' = \dfrac{-5-11}{2}\\\\\\ x'' = \dfrac{-16}{2}}\\\\\\ \large\boxed{\boxed{x''= -8.}}\\\\\\\\ \large\boxed{\boxed{ x' = 3~ e~ x'' = -8.}}$

Espero que te ajude :).