Question

Use a lei do senos e determine o valor de x em cada triangulo

Answer 1

Resposta:

A) sen30°=1/2    sen45°=(√2)/2

$\frac{20}{\sqrt{2}/2} = \frac{x}{1/2}$

$\frac{x\sqrt{2} }{2} = 20.0,5$

$x=\frac{10.2}{\sqrt{2}} = \frac{20\sqrt{2} }{2}= 10\sqrt{2}$≅21,2

B)sen60°=(√3)/2

$\frac{15}{1/2} =\frac{x}{\sqrt{3}/2}$

$30=\frac{2x}{\sqrt{3}}$

$x= \frac{30\sqrt{3} }{2} = 15\sqrt{3}$≅26

C)sen70°≈0,9    sen40°≈0,65

$\frac{x}{0,9} =\frac{10}{0,65}$

x=$\frac{10.0,9}{0,65} = \frac{9}{0,65} = 13,8$