Question

usando o teorema de Pitágoras, calcule o valor de x em cada triângulos retângulo abaixo: ​

Answer 1

$\large\boxed{\begin{array}{l}\rm x^2+5^2=(5\sqrt{2})^2\\\rm x^2+25=25\cdot2\\\rm x^2+25=50\\\rm x^2=50-25\\\rm x^2=25\\\rm x=\sqrt{25}\\\rm x=5\end{array}}$

Answer 2

$\large \sf{ x = 5}$

Explicação:

$\large \text{ \sf{ x {}^{2} + 5 {}^{2} = (5 \sqrt{2} ) {}^{2} } }$

$\large \text{ \sf{ x {}^{2} + 25 = 25 \cdot2} }$

$\large \text{ \sf{x {}^{2} + 25 = 50 } }$

$\large \text{ \sf{ x {}^{2} = 50 - 25 } }$

$\large \text{ \sf{x {}^{2} = 25 } }$

$\large \text{ \sf{ x = \sqrt{25} } }$

$\large \sf{x = 5 }$