Question

usando o teorema de Pitágoras calcule o valor de x

Answer 1

PITÁGORAS
${a}^{2} = {b}^{2} + {c}^{2}$
9)
${x}^{2} = {3}^{2} + {4}^{2}$
$x = \sqrt{9 + 16 =}$
$x = \sqrt{25}$
$x = 5$

10)
$x = \sqrt{ {10}^{2} + {6}^{2} }$
$x = \sqrt{100 + 36}$
$x = \sqrt{136}$
$x = 11.66$

Answer 2

Resposta:

9) x = 5

10) x = 8

Explicação passo-a-passo:

Teorema de Pitágoras: a² = b² + c²

$9)\:x^{2} =3^{2} +4^{2}\\x^{2} =9+16\\x^{2} =25\\\sqrt{x^{2} } =\sqrt{25} \\\boxed{x=5}$

$10)\:10^{2} =x^{2} +6^{2} \\100=x^{2} +36\\-x^{2} =36-100\\-x^{2} =-64\:\times(-1)\\x^{2} =\sqrt{64} \\\boxed{x=8}$