Question

usando Bhaskara 2x²-2=0​

Answer 1

Na equação, temos que os coeficientes a, b e c valem:

--> a = 2

--> b = 0

--> c = -2

Calculando delta (discriminante):

$\Delta~=~b^2-4ac~=~0^2-4.2.(-2)~=~\boxed{16}$

Calculando agora as raízes x' e x'':

$x'~=~\frac{-b+\sqrt{\Delta}}{2a}~=~\frac{-0+\sqrt{16}}{2~.~2}~=~\frac{0+4}{4}~=~\frac{4}{4}~=~\boxed{1}\\\\\\x''~=~\frac{-b-\sqrt{\Delta}}{2a}~=~\frac{-0-\sqrt{16}}{2~.~2}~=~\frac{0-4}{4}~=~\frac{-4}{4}~=~\boxed{-1}$