Question

Usando apenas que log 2 = 0, 30, log 3 = 0, 47 e log 5 = 0, 69, calcule: (f) log 0.5

Answer 1

Resposta:

f)

$log0,5\\ \\ =log{5\over10}\\ \\ =log5\div log10\\ \\ =0,69-1\\ \\= -0,31$